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jasenka [17]
3 years ago
5

Which one of the following pairs of sets has no members in common?

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

{all multiples of three} , {all multiples of four}

Step-by-step explanation:

hope it helps u

pls mark me as branliest

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Simplify completely 10x6y3+20x3y2/5x3y​
Kryger [21]

Answer:

\large\boxed{\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=2x^3y^2+4y}

Step-by-step explanation:

\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=\dfrac{(5x^3y)(2x^3y^2)+(5x^3y)(4y)}{5x^3y}\\\\=\dfrac{5x^3y(2x^3y^2+4y)}{5x^3y}\qquad\text{cancel}\ 5x^3y\\\\=2x^3y^2+4y

8 0
3 years ago
Can someone help with this?
Bumek [7]
4.5/3 = x/5

then:

x = 5 * 4.5 / 3 = 15/2 = 7.5


hope that helps

6 0
3 years ago
Simplify (3^3)(1/9^2 − 6 + 2)
AnnZ [28]

Answer:

27/77

Step-by-step explanation:

I hope this is correct

Have a good Day!

3 0
3 years ago
Write x2 - 8x + 13 = 0 in the form (x - a)2 = b, where a and b are integers. a.)(x - 4)2 = 3 b.) (x - 3)2 = 2 c.)(x - 2)2 = 1 d.
loris [4]
The answer is <span>a.)(x - 4)2 = 3.

(x - a)</span>² = b can be expressed as:
x² - 2ax + a² = b                                 ⇒ x² - 2ax + a² - b = 0

Our equation is                x² - 8x + 13 = 0.
The general formula is    x² - 2ax + (a² - b) = 0

Thus:
8x = 2ax    and a² - b = 13

Divide both sides of the first equation (8x = 2ax) by x:
8 = 2a           ⇒ a = 8 ÷ 2 = 4

Replace a in the second equation (a² - b = 13):
4² - b = 13     ⇒ b = 4² - 13 = 16 - 13 = 3

Now when we have a and b, let's just replace them in the general equation:
(x - a)² = b
(x - 4)² = 3
4 0
3 years ago
What is the product? Two-thirds times eight-ninths StartFraction 10 over 27 EndFraction StartFraction 16 over 27 EndFraction Two
melomori [17]

Answer:

16/27

Step-by-step explanation:

First let's convert this info an equation and then we will solve.

(2/3) * (8/9) = ?

( 2 * 8 ) / ( 3 * 9 ) = ?

( 16 ) / ( 27 ) = ?

16 / 27 = ?

So our fractional answer is 16/27.

In words this would be sixteen over twenty seven.

Cheers.

3 0
2 years ago
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