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eimsori [14]
3 years ago
7

Identify an equation in point-slope form for the line perpendicular to y= 3x+ 5.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

y+1=-1/3(x-4)

Step-by-step explanation:

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Can someone help me pls
Andrej [43]

Answer:

x=78

Step-by-step explanation:

q is 90 degrees since it is a right angle,

p=12

90 plus 12 =102

x=180-102

x=78

3 0
3 years ago
Read 2 more answers
a high school track teams long jump record is 21 feet and 2 1/4 inches. this year Tims best long jump is 20 feet and 9 1/2 inche
Alex787 [66]

Answer:

4.75 inches.

Step-by-step explanation:

We must introduce the symbols for inches and feet.

Here we will use, x' = x feet and x" = x inches

A high school track teams long jump record is 21 feet and 2\dfrac{1}{4} inches i.e. 21'2.25" this year.

Now, Tim's best long jump is 20 feet and 9\dfrac{1}{2} inches i.e. 20'9.5".

So, the difference between the record jump and Tim's best jump is

(21'2.25" - 20'9.5")

= (21'2.25" - 21') + (21' - 20'9.5")

= 2.25" + 2.5" {Since, 1' = 12" i.e. 21' = 20' 12"}

= 4.75"

Therefore, Tim has to jump 4.75 inches farther to break the record. (Answer)

3 0
3 years ago
3) Lane and Zack purchased a house for $245,000 in 2016. The house loses 4% of its value each year,
alina1380 [7]

Answer:

$138,345

Step-by-step explanation:

This is a compound decline problem, which will be solve by the compound formula:

F=P(1-r)^t

Where

F is the future value (value of house at 2030, 14 years from  2016)

P is the present value ($245,000)

r is the rate of decline, in decimal (r = 4% = 4/100 = 0.04)

t is the time in years (2016 to 2030 is 14 years, so t = 14)

We substitute the known values and find F:

F=P(1-r)^t\\F=245,000(1-0.04)^{14}\\F=245,000(0.96)^{14}F=138,344.96

Rounding it up, it will be worth around $138,345 at 2030

8 0
3 years ago
Consider the diagram.<br> What is the length of segment AB?
Vlad [161]
The answer would be B
6 0
3 years ago
Two-dimensional objects are measured
balandron [24]
It’s either length or area.
6 0
3 years ago
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