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2 years ago

Let AB // ED , AB = 10 units, AC = 12 units, and DE = 5 units. What is the length of AD?

Mathematics

1 answer:

zheka24 [161]2 years ago

4 0

Answer:

length of CD = 18 units.

Step-by-step explanation:

In ΔABC and ΔCED,

AB║DE and AD is a transversal line,

m∠ABC = m∠CED [Alternate interior angles]

m∠ACB = m∠DCE [Vertically opposite angles]

ΔABC ~ ΔCED [By AA property of similarity]

Therefore, by the property of similar triangles, corresponding sides will be proportional.

$\frac{AB}{DE}= \frac{AC}{DC}$

$\frac{10}{5}=\frac{12}{CD}$

CD = 6

Since, AD = AC + CD

AD = 12 + 6

= 18 units

Therefore, length of CD = 18 units.

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Let AB // ED , AB = 10 units, AC = 12 units, and DE = 5 units. What is the length of AD?​

Let AB // ED , AB = 10 units, AC = 12 units, and DE = 5 units. What is the length of AD?