Let AB // ED , AB = 10 units, AC = 12 units, and DE = 5 units. What is the length of AD?
1 answer:
Answer:
length of CD = 18 units.
Step-by-step explanation:
In ΔABC and ΔCED,
AB║DE and AD is a transversal line,
m∠ABC = m∠CED [Alternate interior angles]
m∠ACB = m∠DCE [Vertically opposite angles]
ΔABC ~ ΔCED [By AA property of similarity]
Therefore, by the property of similar triangles, corresponding sides will be proportional.
CD = 6
Since, AD = AC + CD
AD = 12 + 6
= 18 units
Therefore, length of CD = 18 units.
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Answer:
The length of the bottom side of the banner is 17 in.
Step-by-step explanation:
Given,
Area of the Banner =
Height of the Banner = 24 in
Top side of the Banner = 14 in
We have to find the length of the bottom side of the banner.
Solution,
Let the length of the bottom side of the banner be 'x'.
Since the banner is in the shape of trapezoid.
So according to the formula of area of trapezoid, which is;
Area of trapezoid =
Here top and bottom sides are parallel and distance between them is equal to the height of the banner.
Now substituting the values, we get;
Hence The length of the bottom side of the banner is 17 in.