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3 years ago

X - 4 = -4 - 4 2 - 3x = -x - 8 Please help me solve these

1 answer:

5 0

X - 4 = -4 -4

Combine the two -4.

X - 4 = -8

Add 4 on both sides to isolate the x and get your answer.

X = -4

2 - 3x = -x - 8

Subtract the 2 on both sides.

-3x = -x - 10

Add the x on both sides.

-2x = -10

Divide by -2 on both sides to isolate the x and get your answer.

x = 5

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AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$

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Answer:

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B. ∠B ≅ ∠E

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Step-by-step explanation:

Transformation involves the reshaping or resizing of a given figure. The types are: reflection, dilation, rotation and translation.

In the given question, the two operations performed on triangle ABC are reflection and dilation to form triangle DEC. The length of each side of triangle DEC is two-third of that of ABC. Therefore, the correct statements about the two triangles are:

i. △ABC ~ △DEC

ii. ∠B ≅ ∠E

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