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MaRussiya [10]
3 years ago
6

Use a proportion to solve the problem. Round to the nearest tenth as needed. A triangle drawn on a map has sides of lengths 9 cm

, 11 cm, and 15 cm. The shortest of the corresponding real-life distances is 101 km. Find the longest of the real-life distances.
Mathematics
1 answer:
Volgvan3 years ago
8 0
X/15=101/9
x= 505/3
x= 168.3 
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What is the answer to x^2-11=25 please
Westkost [7]

Hey there!

\mathsf{x^2 - 11 = 25}

\large\textsf{ADD 11 to BOTH SIDES}

\mathsf{x^2 - 11 + 11 = 25 + 11}

\large\textsf{CANCEL out: -11 + 11 because that gives you 0}

\large\textsf{KEEP: 25 + 11 because that helps solve for the x-value}

\mathsf{25 + 11 = \bf 36}

\large\textsf{NEW EQUATION: }\mathsf{x^2=36}

\large\textsf{Take the square root of the number (36)}

\mathsf{x = \pm \sqrt{36}}

\mathsf{\pm = \boxed{\bf plus-or-minus}}

\mathsf{x = \sqrt{-36}\rightarrow \bf -6}

\large\textsf{or}

\mathsf{x = \sqrt{36} = \bf 6}

\boxed{\boxed{\huge\textsf{Answer: \bf x = 6 or x = -6}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

5 0
3 years ago
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