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Wittaler [7]
3 years ago
8

1.Write an equation of the line in point-slope

Mathematics
1 answer:
Oduvanchick [21]3 years ago
6 0

Answer:

<u>Point slope form</u>

y-10 = -6 (x+1)

<u>Slope-intercept form</u>

y=-6x+4

<u>Standard form</u>

4x+y=4

Step-by-step explanation:

Equation in Point slope form is

y-y_1=m (x-x_1) ---------- (1)

Here

m=-5 \ \ \ and \ \ \ (x_1, y_1) = (-1, 10)

Substituting values in equation (1)

y-10 = -6 (x+1) ------------- (2)

Equation (2) is equation of line in point slope form.

<u>Re-arranging equation (2)</u>

y = -6x - 6 + 10

y=-6x+4 ----------- (3)

Equation (3) is equation of straight line in slope-intercept form

<u>Re-arranging equation (3)</u>

<u />4x+y=4   --------(4)

Equation (4) is equation of line in standard form

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Work out the surface area of this cylinder radius 2cm and height 4cm pls help​
Alex

Step-by-step explanation:

surface area of cylinder is

2×pi×r (h+r)

2×22/7×2 (4+2)

88/7 (4+2)

75.4 cm square

6 0
3 years ago
Find the equation of the line passing through the points (2,1) and (5, 10) <br><br>y = 3x + ?
storchak [24]

Answer:

y = 3x -5

Step-by-step explanation:

y = mx + b

for (5, 10)

b = y - mx = 10 - 3 x 5 = - 5

y = 3x -5

for (2,1)

check: 1 = 2 x 3 -5

7 0
3 years ago
Jessica is shopping for a sweater the one she wants is 30%off she estimated the sale price by multiplying the original price by
Butoxors [25]
Multiplying 0.7 by the original price will work...

If you divide the cost by 100, subtract 30 from 100, you will be left with 70% times the 1/100
70% is also expressed as 0.7, since 7/10=70/100

Hope this helps!

8 0
3 years ago
Desmond deposits $50 into a savings account every month at an annual interest rate of
joja [24]

Given:

Desmond deposits $ 50 monthly.

Yearly he deposits = $50×12 = $ 600

Rate of interest compounded monthly = 4.7%

To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.

Formula

A = P(1+\frac{r}{(n)(100)} )^{nt}

where,

A be the final amount

P be the principal

r be the rate of interest

t be the time and

n be the number of times the interest is compounded.

Now,

Taking,

P = 600, r = 4.7, n = 12, t = 10 we get,

A = 600(1+\frac{4.7}{(12)(100)}) ^{(12)(10)}

or, A = 600(1.0039)^{120}

or, A = 959.1

Now,

At starting he has $ 600

At the end of 10 years he will be having $ 959.1

So,

The amount of change in his account = $ (959.1-600) = $ 359.1

Therefore the rate of change = (\frac{359.1}{600} )(100) %

= 59.85%

Hence,

a) His account will contain $ 959.1 after 10 years.

b) The rate of change in his account is 59.85% after 10 years.

7 0
3 years ago
PLEASE PLEASE PLEASE HELP ASAP *grade 9 work* best answer gets brainliest :)
skelet666 [1.2K]
For number 13 x=70 and y=115 hope this helped
7 0
3 years ago
Read 2 more answers
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