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3 years ago

In 1990, the population of the Midwest was about 60 million. During the 1990s, the population of

1 answer:

7 0

In 1990, the population of the Midwest was about 60 million. During the 1990s, the population of this area increased an average of about 0.4 million per year. The population of the West was about 53 million in 1990. The population of this area increased an average of about 1 million per year during the 1990s. Assume that the rate of growth of these areas remains the same. Estimate when the population of the West would be equal to the population of the Midwest.

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A market sells 6 cans of food for every 7 boxes of food. The market sold a total of 26 cans and boxes today. How many of each ki

Solnce55 [7]

6 cans and 20 boxes

6 0

3 years ago

Read 2 more answers

You kept track of the numbr of minutes you spent on homework for one week. 18, 20, 22, 11, 19, 18, 18 What is range of minutes y

frosja888 [35]

Answer:

your range is 11

Step-by-step explanation:

22-11= 11

4 0

3 years ago

Of the 85% of the students in a class who studied for a test,75% passed the test.Of the 15% of the students who didn't study,30%

galina1969 [7]

Probability works for any given number, so we will assume there are 100 students. Of those 100, 85 of them studied. Since 75% of 85 students passed, we will multiply 85 by 0.75. This gives us 60. So of the students who studied, 60 of them passed. Of the 15 students that didn’t study, 30 percent passed. So we multiply 15 by 0.3. This gives us 4.5 students. Add up 60 and 4.5, and you get 64.5. The probability of passing is 64.5%. If you want to round up, it would be 65%. If you want to round down, it would be 64%. But the most precise answer is 64.5%.

3 0

3 years ago

Consider the spreading of a rumor through a company of 1000 employees, allworking in the same building.We assume that the spread

natima [27]

Answer:

On the 12th day, the rumor would have has to all the 1000 employees

Step-by-step explanation:

Given the data in the question;

so, lets consider the rumor spreading thorough the company of 1000 employee;

the given model is; $r_{n+1}$ = $r_{n}$ + 1000k $r_{n}$ ( 1000 - $r_{n}$ )

where k is the parameter that depends on how fast the rumor spreads, n is the number of days.

now, lets assume k = 0.0001, lets also assume r₀ = 4

so to find how soon all 1000 employees will have heard the rumor ;

let n be;

then r1 will be;

r1 = r₀ + ( 0.001)r₀(1000-r₀ )

r1 = 4 + ( 0.001) × 4× (1000 - 4 )

r1 = 7.984

r2 will be;

r2 = r1 + ( 0.001)r1(1000-r1 )

r2 = 7.984 + ( 0.001) × 7.984 × (1000 - 7.984 )

r2 = 15.904255744

r3 will be;

r3 = r2 + ( 0.001)r2(1000-r2 )

r3 = 15.904255744 + ( 0.001) × 15.904255744 × (1000 - 15.904255744 )

r3 = 31.555566137

Using the same formula and procedure by substituting n = 1,2,3,4,5,6,7,8,9,10,11,12.

we will have;

n rₙ

0 4

1 7.984

2 15.904255744

3 31.555566137

4 62.1153785

5 120.372437

6 226.25535

7 401.319217

8 641.58132

9 871.53605

10 983.497013

11 999.727651

12 999.999926

Therefore, On the 12th day, the rumor would have has to all the 1000 employees

5 0

3 years ago

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

3 years ago