Answer:
6 ft
Step-by-step explanation:
Given that:
Length of rectangular banner = 18 ft
Total trim of banner available = 48 ft
To find:
Possible widths of the banner = ?
Solution:
Maximum trim available of the banner around the entire border of the banner = 48 ft
i.e. we are given the total perimeter of the rectangular banner.
Formula for perimeter of a rectangle is given as:

Putting the values of perimeter and length to find the value of width.

So, width possible is <em>6ft.</em>
n - 4 = 16 Given
+ 4 + 4 Cancel out 4 to isolate n variable
n = 20
Prove.
20 - 4 = 16
16 = 16
True.
Answer:
2 6/30 and 1 25/30
Step-by-step explanation:
First, you need to find 30÷5 and 30÷6. You do this because you need to know the multiplier when you create an equivalent fraction. 30÷5 is 6 and 30÷6 is 5. 2 1/5. You need to multiply the 1 and 5 by 6, that is 2 6/30. 1 5/6. 5 and 6 multiplied by 5 is 25 and 30. 1 5/6=1 25/30
Answer:

Step-by-step explanation:
From the image, f(x) and x are rlated by

where b is the common ratio
We first find the value for b





so we can say the common ratio, b=5
we put in any value of f(x) and the corresponding value for x to find a value
Let put x=0 and f(x)=5120
This implies that

but

Hence a=5120
Thus the equation which model the relationship between the weeks and the viewers is
