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3 years ago

I am a fraction greater than 1/2 and less than 6/8

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

5/8

Step-by-step explanation:

it is 5/8 because if it is greater than1/2, which =to 4/8, and less than 6/8, it must be the number in between, which is 5/8

VladimirAG [237]3 years ago

5 0

3/4 because 1/2 equals 50% and 1/4 plus that would be 75% less than 6/8

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navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

<u>Step 1: Multiply</u>

<u /> $(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

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$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

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MA_775_DIABLO [31]

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JulsSmile [24]

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