The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
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Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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Answer : 96
x – y = 16 --------> equation 1
1/8 x + 1/2 y = 52
x is the higher grade and y is the lower grade
We solve the first equation for y
x - y = 16
-y = 16 -x ( divide each term by -1)
y = -16 + x
Now substitute y in second equation
1/8 x + 1/2 ( -16 + x ) = 52
1/8x - 8 + 1/2 x = 52
1/8x + 1/2x - 8 = 52
Take common denominator to combine fractions
1/8x + 4/8x -8 = 52
5/8x - 8 = 52
Add 8 on both sides
5/8x = 60
Multiply both sides by 8/5
x = 96
We know x is the higher grade
96 is the higher grade of Jose’s two tests.
Answer:
Volume of a cylinder: V = π * r² * h ,
Base surface area of a cylinder: A_b = 2 * π * r² ,
Lateral surface area of a cylinder: A_l = 2 * π * r * h ,
Total surface area of a cylinder: A = A_b + A_l ,
Step-by-step explanation:
So, when the radius is tripled, the volume will be 3 squared = 9 times than the previous one.
