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3 years ago

Use the distributive property to simplify 1/6 × (36+1/2)

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

1/6(36 + 1/2) = 6 + 1/12 = 72/12 + 1/12 = 73/12

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What is the measure of angle 2

gulaghasi [49]

22 just kidding........ 16

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3 years ago

A stairway rises 6 feet 4 inches over a horizontal distance of 8 feet 6 inches. What is the diagonal length of the stairway

natali 33 [55]

Answer:

10.6 ft

Step-by-step explanation:

to find the diagonal length of the stairway we can use the pythagorean theorem or a^2 + b^2 = c^2

6'4" is also 6 1/3' or 19/3'

8'6" is also 8 1/2' or 17/2'

now square them both

361/9 + 289/4

make them have the same denominator

1444/36 + 2601/36

add them

4045/36

take the square root

10.6000524 is your answer

10.6 ft

7 0

2 years ago

the path of a rocket can be modeled by the function h(t) =-16t(t-5) seconds and h is the height in feet.

AnnyKZ [126]

-16 feet x -5 seconds = 80ft/s

4 0

3 years ago

Three different fraction equivalent 1

olga nikolaevna [1]

Answer:

3/3, 9/9, 12/12

Step-by-step explanation:

Equivilant fractions are only the ssame number on top of each other OR a number on top of a 1

7 0

3 years ago

Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti

sukhopar [10]

The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

At Morning, the probability that Marvin does not teleport = 2/3

Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = $\frac{2}{3}*\frac{2}{3}=\frac{4}{9}$

Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.

Probability that Marvin teleports atleast once during the day = $1-\frac{4}{9}=\frac{5}{9}$

5 0

3 years ago