There are 540 fuses in total and the original price of the internet is $55.91
<h3>
How to work with percentages?</h3>
a) We know that 5% of the fuses are faulty, and there are 27 faulty fusses, then we can write:
5% = 27
100% = x
We want to find x, to do that, we can write:
x = 27*(100%/5%) = 27*20 = 540
There are 540 fuses in total.
b) Now we know that the original price is P, and when we decrease it by 7%, then new price is $52.00
Then we can write:
$52.00 = P*(1 - 7%/100%)
$52.00 = P*(0.93)
$52.00/0.93 = P = $55.91
The original price is $55.91
If you want to learn more about percentages:
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Answer:
no c
Step-by-step explanation:
yo no c le dire un experto que vea to pregunta
Answer:
1/63
Step-by-step explanation:
Here is the complete question
In an experiment, the probability that event A occurs is 1
/7 and the probability that event B occurs is 1
/9
.
If A and B are independent events, what is the probability that A and B both occur?
Simplify any fractions.
Solution
the probability of independent events A and B occurring is P(A u B) = P(A)×P(B) where P(A) = probability that event A occurs = 1
/7 and P(B) = probability that event B occurs = 1
/9
.
So, P(A u B) = P(A)×P(B) = 1/7 × 1/9 = 1/63
I think the equation is
y=-1/3x +10/3
(1/3x+y=10/3)•3
x+3y=10, is the answer
The answer is D, 8$. One easy way to do it is to take 10% of 40, which is 4, and double it.
