In an experiment, the probability that event A occurs is 1
/7 and the probability that event B occurs is 1
/9
.
If A and B are independent events, what is the probability that A and B both occur?
Simplify any fractions.
Solution
the probability of independent events A and B occurring is P(A u B) = P(A)×P(B) where P(A) = probability that event A occurs = 1
/7 and P(B) = probability that event B occurs = 1
/9
.
For two events A and B which are independent events, the probability of A occurring does not affect the probability of B occurring and vice versa. Therefore the probability of both event occurring is equal to the product of their individual probabilities.
Given that: P(A) = and P(B) = .
Probability that A and B both occur = P(A and B) = P( A ∩ B) = P(A) P(B)
So one coat uses 125 chinchillas . So, 10 * 125 will give you how many will give you 1250 chinchillas.. this is the number of chinchillas needed for 10 coats. So for 2 years you would have to multiply it by two so, 1250 * 2 = 2500.
What you would do is you would keep subtracting (I recommend a calculator for this task) from both accounts until you get an equal amount for each. You would also have to record this down that way you know each time what you got. (And please do not put the calculator part). Really hope this helps!!!
