Question

In an experiment, the probability that event A occurs is

Answer 1

Answer:

1/63

Step-by-step explanation:

Here is the complete question

In an experiment, the probability that event A occurs is  1 /7  and the probability that event B occurs is  1 /9 .

If A and B are independent events, what is the probability that A and B both occur?

Simplify any fractions.

Solution

the probability of independent events A and B occurring is P(A u B) = P(A)×P(B) where P(A) = probability that event A occurs =  1 /7 and P(B) = probability that event B occurs =  1 /9 .

So,  P(A u B) = P(A)×P(B) = 1/7 × 1/9 = 1/63

Answer 2

Answer:

$\frac{2}{7}$

Step-by-step explanation:

For two events A and B which are independent events, the probability of A occurring does not affect the probability of B occurring and vice versa. Therefore the probability of both event occurring is equal to the product of their individual probabilities.

Given that: P(A) = $\frac{2}{3}$ and P(B) = $\frac{3}{7}$.

Probability that A and B both occur = P(A and B) = P( A ∩ B) = P(A) P(B)

Therefore P(A and B) = $\frac{2}{3}*\frac{3}{7} =\frac{2}{7}$

P(A and B) = $\frac{2}{7}$