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3 years ago

Then find the area S of the region. y=2 x^2, y^2=1/2 x

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

3 0

Recall that the area under a curve and above the x axis can be computed by the definite integral. If we have two curves

y = f(x) and y = g(x)

such that

 f(x) > g(x)

then the area between them bounded by the horizontal lines x = a and x = b is

To remember this formula we write

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What is the formula of a radius circle ?

UkoKoshka [18]

I assume you happen to mean, what is the formula for a circle.

The formula is:

A= $\pi r^{2}$

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3 years ago

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Find the area of a regular hexagon

xxMikexx [17]

<h2>Answer:</h2><h2>42 cm^2</h2>

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3 years ago

3(Ꮾ - f) -4 = 3f - 4

raketka [301]

3(6-f)-4=3f-4

First is expand

18-3f-4=3f-4

Combine like terms

14-3f=3f-4

18-3f=3f

18=6f

f=3

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3 years ago

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Need some help please <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B15%7D%20%20%2B%20%28%20-%20%20%5Cfrac%7B3%7D%7B

emmasim [6.3K]

Answer:

-1/60

Step-by-step explanation:

$\frac{11}{15} + (- \frac{3}{4} )\\$

= $\frac{11}{15} - \frac{3}{4}\\$

= $\frac{44}{60} - \frac{45}{60}\\$ (find LCM of demoninators)

= $\frac{44-45}{60}\\$

= $\frac{-1}{60}\\$

= -1/60

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3 years ago

The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how ma

Natalka [10]

$b=a+3\\
c=a+6\\
a^2+b^2=c^2\\\\
a^2+(a+3)^2=(a+6)^2\\
a^2+a^2+6a+9=a^2+12a+36\\
a^2-6a-27=0\\
a^2-9a+3a-27=0\\
a(a-9)+3(a-9)=0\\
(a+3)(a-9)=0\\
a=-3 \vee a=9\\
$

The length can't be negative, so the answer is 9 cm.

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2 years ago

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