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levacccp [35]
3 years ago
9

Find the equation of the exponential function represented by the table below:

Mathematics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

y=2^{1-x}

Step-by-step explanation:

<u>Exponential Function</u>

When we need to express the exponential relation between two variables, we use the equation

y=Cr^{x}

where C, r are constants to be determined by using the given points from the table

For x=0, y=2, thus

2=C.r^{0}=C

We find that C=2

The equation is now

y=2r^{x}

Now we use the point x=1, y=1

1=2r

We find that

\displaystyle r=\frac{1}{2}

Thus, the equation is

\displaystyle y=2\left(\frac{1}{2}\right)^{x}

Rearranging

y=2(2)^{-x}=2^{1-x}

The required equation is

y=2^{1-x}

We can easily verify the last two points are also obtained by using the equation

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What is the rate of decay for the function f(x) =2(0.95)^x ( x is on top of the parentheses)
SIZIF [17.4K]

Answer:

The decay rate is 5%.

Step-by-step explanation:

Let a substance is decaying at the rate of r% per hour from the initial value of P for t hours, then the final value of the substance is given by the function  

f(t) = P(1 - \frac{r}{100})^{t} ........... (1)

Comparing this equation with the original equation given as

f(x) = 2(0.95)^{x} ............ (2) we get,

(1 - \frac{r}{100}) = 0.95

⇒ \frac{r}{100} = 0.05

⇒ r = 5%.

Therefore, the decay rate is 5%. (Answer)

7 0
3 years ago
Find the volume of the prism (Picture Provided)
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A triangle has side lenghts 10cm, 24cm, and 34cm. is the triangle acute, obtuse, or right?
Sergeu [11.5K]
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3 years ago
Whats the value of e? -(4e+7)=1
LekaFEV [45]

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-2

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-4e-7=1

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4 0
2 years ago
Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 &lt; Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

where <em>µ</em> = -16 and <em>σ</em> = 1.21.

Pr[-15.043 < <em>Y</em> ≤ <em>k</em>] = 0.1546

Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

Take the inverse CDF of both sides (<em>Φ(x)</em> denotes the CDF itself):

(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

Solve for <em>k</em> :

<em>k</em> + 16 = 1.21 • 1.556

<em>k</em> ≈ -14.118

8 0
3 years ago
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