Well first we should simplify:
![\sqrt[5]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3%7D%20)
+ ![\sqrt[2]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7B3%7D%20)
This turns into:
![\sqrt[7]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B3%7D)
This turns into:
Plllls help me with these three I will make brainlesst pls no links
1 answer:
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For a Cloudy sky , the solar panel requires 80 hours to generate 400 kilowatts per day
For a clear sky the solar panel requires 12.5 hours to generate 400 kilowatts per day.
The solar panel does not exceed its maximum capacity of 400 kilo watts per day because it will generate 207 kilo watts per day.
Step-by-step explanation:
1.Given the inequality for power generated as;
5C+32L≤400 where C is number of hours when sky is cloudy and L is the number of hours when the sky is clear then;
The equation can be written using x and y as
5x + 32 y ≤ 400 -----where x=C and y=L
Graphing the equation on a graph tool for values of x and y that produce maximum capacity,the graph is attached below where x=80 hours and y=12.5 hours.
This means C=cloudy sky = 80 hours and L=clear sky= 12.5 hours
For a Cloudy sky , the solar panel requires 80 hours to generate 400 kilowatts per day
For a clear sky the solar panel requires 12.5 hours to generate 400 kilowatts per day.
2.
Given C=3 hours and L= 6 hours substitute values in the inequality
5C+32L≤400
5*3 + 32*6 ≤ 400
15+192 ≤ 400
207 ≤ 400
The solar panel does not exceed its maximum capacity of 400 kilo watts per day.
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Inequalities :brainly.com/question/10921764
Keywords: solar panel, power, maximum rate, sky, cloudy, clear,
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