Part A
4x10 – 64x2
= 4x2 * x8 – 4x2 * 16
= 4x2 * (x8 – 16) by distributive property
Part B
x8 is (x4)2 and 16 = 42 so a difference of squares is seen in the parentheses. The pattern a2 – b2 = (a + b)(a – b) can be used.
4x2 * (x8 – 16)
= 4x2 * (x4 + 4) * (x4 – 4)
x4 = (x2)2 and 4 = 22 so there is another difference of squares in the last factor. Use the pattern again.
= 4x2 * (x4 + 4) * (x2 + 2) * (x2 – 2)
48=16-0.5x
add 0.5 both sides
0.5x+48=16
mnus 48 boh sides
0.5x=-32
times 2 both sides
x=-64
Answer:
Check below for the answers
Step-by-step explanation:
Note: The options are not clearly expressed but below are the correct expressions for the trigonometric identities stated in the options.
Using the SOHCAHTOA principle
sin θ = Opposite / Hypotenuse
tan θ = opposite / Adjacent
Cot θ = 1 / tan θ = Adjacent / Opposite
cos θ = Adjacent / Hypotenuse
I hope this helps you
this triangle is isosceles right triangle
base=height
Area=base×height /2
18=b×b/2
b^2=36
b=6
