Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
Answer:
<h3>A. y=-2x+3z+25</h3>
Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
<u>To solve:</u>

<h3>2x+y-3z=25</h3>
<u>First, you have to subtract by 2x-3z from both sides.</u>

<u>Solve.</u>

- <u>Therefore, the correct answer is "A. y=-2x+3z+25".</u>
I hope this helps, let me know if you have any questions.
Sosksl 35is40 is 40 times 0 is 3
The answer is 7.66 repeating. I hope this helps