584 is the total number of students in the school.
5/8 are in seventh grade and 3/8 are in eighth grade.
4/5 of the seventh graders participated in the track meet, so there were (4/5 · 5/8) · 584 students in the seventh grade participating in the track meet.
7/8 of the eighth graders participated, so there were (7/8 · 3/8) · 584 students in the eighth grade participating in the track meet.
So, all together, there were
(4/5 · 5/8) · 584 + (7/8 · 3/8) · 584 students from the school in the track meet.
Let's simplify as you asked:
(4/5 · 5/8) · 584 + (7/8 · 3/8) · 584 = [(4/5 · 5/8) + (7/8 · 3/8)] · 584 (distributive property - factoring)
= [20/40 + 21/64] · 584 (multiply fractions)
= (1/2 + 21/64) 584 (reduce the first fraction to lowest terms)
= (32/64 + 21/64) 584 (getting a common denominator)
= (53/64) 584 (combine/add the two fractions)
= 483.625 (multiply together)
All together, there were: 483.625 students in the meet.
Answer:
156
Step-by-step explanation:
Answer:
no
Step-by-step explanation:
three points can exist on three different lines and still reside in the same plane
You cannot assume the angles add to 90, but you know since BD is an angle bisector that ABD is equal to DBC, or x-5=2x-6
x=1. this is the correct solution to the equation but gives negative angles when plugged in which isn't possible. there must be something wrong work the question
