Answer:
Kindly check explanation
Step-by-step explanation:
Given :
Sample size, n = 30
Tcritical value = 2.045
Null hypothesis :
H0: μ = 9.08
Alternative hypothesis :
H1: μ≠ 9.08
Sample mean, m = 8.25
Samole standard deviation, s = 1.67
Test statistic : (m - μ) ÷ s/sqrt(n)
Test statistic : (8.25 - 9.08) ÷ 1.67/sqrt(30)
Test statistic : - 0.83 ÷ 0.3048988
Test statistic : - 2.722
Tstatistic = - 2.722
Decision region :
Reject Null ; if
Tstatistic < Tcritical
Tcritical : - 2.045
-2.722 < - 2.045 ; We reject the Null
Using the α - level (confidence interval) 0.05
The Pvalue for the data from Tstatistic calculator:
df = n - 1 =. 30 - 1 = 29
Pvalue = 0.0108
Reject H0 if :
Pvalue < α
0.0108 < 0.05 ; Hence, we reject the Null
Answer:
131.95cm.
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
Answer: yes
Step-by-step explanation:
We have to determine the value of 
= (5(9)+6) + (5(10)+6) +(5(11)+6) + .......... + (5(21)+6)
= 51+56+61+66+ ........ + 111
Since, the common difference is 5, hence this series is in arithmetic progression.
Sum of AP is given by the formula:
![\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Since, there are 13 terms.
= ![\frac{13}{2}[2(51)+(13-1)5]](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B2%7D%5B2%2851%29%2B%2813-1%295%5D)
= ![\frac{13}{2}[102+60]](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B2%7D%5B102%2B60%5D)
= ![\frac{13}{2}[162]](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B2%7D%5B162%5D)
= 
= 1053
Therefore, the sum of the series is 1053.
So, Option G is the correct answer.
