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2 years ago

I need help on this question anything help

Mathematics

1 answer:

elixir [45]2 years ago

4 0

Answer:

y = -3x - 1

Step-by-step explanation:

Look at your line. It's a downward trend which means your slope is negative

slope is the m in y = mx+b

Your b is your y intercept or where the graph touches the y = 0 vertical line.

It cross at -1 value

Your slope value is determined by rise/run so in the case it goes down 3 values and across 1 value so its 3/1 but its negative so its -3/1

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A square corner of 16 square centimeters is removed

oee [108]

Option C:

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter

Solution:

Area of the square paper = $9x^2$ sq. cm

Area of the square corner removed = 16 sq. cm

Let us find the area of the remaining paper.

Area of the remaining paper = Area of the square paper – Area of the corner

Area of the remaining = $9x^2-16$

= $(3x)^2-(4)^2$

Using algebraic formula: $a^2-b^2=(a+b)(a-b)$

$=(3x-4)(3x+4)$

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter

Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.

8 0

2 years ago

Read 2 more answers

3/8 times what equals 1

horsena [70]

3/8 times 8/3 = 1
Answer=8/3

6 0

2 years ago

Combine like terms : 2x+5x+10x

8090 [49]

Answer: =17x

Step-by-step explanation: hope this help, hope you understand it too.

Let's simplify step-by-step.

2x+5x+10x

Combine Like Terms:

=2x+5x+10x

=(2x+5x+10x)

=17x

7 0

2 years ago

Please write the answer

Travka [436]

$\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\ \\ \longrightarrow \sf \: 27 - 15 \\ \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}$

6 0

2 years ago

Please help really need to pass

VashaNatasha [74]

First add 5 to right side
$\frac{x}{7} = -4+5 = 1$
Next , to cancel the 7, you need to multiply by 7 on both sides
$x = 1*7 = 7$

8 0

3 years ago