Answer:
and 
Step-by-step explanation:
A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.
In when x=3, y=15/4≈2.14
In 
when x=3, y=1.8
In when x=3, y≈2.33
In 
when x=3, y≈1.90
We can observe that in two cases, and , y is greater than 2.
They're all d).
1) 28>24=10+14
2) Either 96/8=? or 8*?=96 describe the problem, ? being the number of chairs (the blank square in the answers). Of the two only the first appears in the options.
3) This question is ambiguous: if someone went both days, we could say the total number of people who went to the Saturday and Sunday games would be less than 3271+5844=9115. But who wrote the question likely wanted you to just do the sum between the two numbers, so of all options d is likely what they want you to choose.
<span>y = kx
x = y/k if y = 0.33 a</span><span>nd k = 1/4
x = 0.33/0.25
x = 1.32
answer
</span><span>D) 1.32</span>
Answer:
AD = 84
Step-by-step explanation:
Since B is the midpoint of AC then AB = BC = 2x - 5
Since C is the midpoint of AD then AC = CD, thus
AB + BC = CD, that is
2x - 5 + 2x - 5 = x + 29
4x - 10 = x + 29 ( subtract x from both sides )
3x - 10 = 29 ( add 10 to both sides )
3x = 39 ( divide both sides by 3 )
x = 13
Hence
AD = AB + BC + CD
= 2x - 5 + 2x - 5 + x + 29 = 5x + 19, thus
AD = (5 × 13) + 19 = 65 + 19 = 84
