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3 years ago

Which of the following polynomial represents a difference of squares?

Mathematics

1 answer:

Misha Larkins [42]3 years ago

5 0

Heres an example x2- 16 when u solve or factor u should get the difference of two squares of (x+2) (x-2)

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Two sides of an isosceles triangle have lengths of 3 and 10. Find the length of the third side.

lora16 [44]

Answer:

The third side must be 10: {3, 10, 10}; {10, 3, 3} is not possible.

Step-by-step explanation:

Everything depends on our understanding of "isosceles."

This term indicates that two sides of a given triangle are equal.

If two sides of an isosceles triangle have lengths of 3 and 10, then:

Either 1) Two sides have length 10 and the third side has length 3. This is certainly possible

2) sides have length 3 and the third side has length 10. This is NOT possible, since 3 + 3 adds up to 6, which is less than 10.

8 0

3 years ago

What is 1.5 Devided by 1

VARVARA [1.3K]

Answer:

1.5

Step-by-step explanation:

Anything divided by 1 is itself

6 0

3 years ago

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Monica wants to rent online movies. The company Movies Plus charges a one-time fee of $20 plus $5 per movie. Movies-2-Go charges

UkoKoshka [18]

Answer:

Step-by-step explanation:20+5+7=32

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3 years ago

Students from grades 11 and 12 in Jason's school were asked to vote for the prom king and queen. Jason surveyed every 12th stude

statuscvo [17]

Tyler Will Get 28 Votes And Katie Will Get 27

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3 years ago

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Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat

stiks02 [169]

Answer:

Part A

b. 14.6 ± 7.38

Part B

b. 3.43

Part C

a. P-value < 0.01

Part D

b. There is sufficient evidence to reject the null hypothesis

Step-by-step explanation:

Part A

The given data are;

The number of seedlings in the field = 20

The number of seedlings selected to receive herbicide A = 10

The number of seedlings selected to receive herbicide B = 10

The height in centimeters of seedlings treated with Herbicide A, $\overline x _1$ = 94.5 cm

The standard deviation, s₁ = 10 cm

The height in centimeters of seedlings treated with Herbicide B, $\overline x _2$ = 109.1 cm

The standard deviation, s₂ = 9 cm

The 90% confidence interval for μ₂ - μ₁, is given as follows;

$\left (\bar{x}_{2}- \bar{x}_{1} \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}$

The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;

The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18

α = 100% - 90% = 10%

∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05

$t_{(0.025, \, 18)}$ = 1.734

$C.I. = \left (109.1- 94.5 \right )\pm 1.734 \times \sqrt{\dfrac{10^{2}}{10}+\dfrac{9^{2}}{10}}$

C.I. ≈ 14.6 ± 7.37714603353

The 90% C.I. ≈ 14.6 ± 7.38

b. 14.6 ± 7.38

Part B

With the hypotheses are given as follows;

H₀; μ₂ - μ₁ = 0

Hₐ; μ₂ - μ₁ ≠ 0

The two sample t-statistic is given as follows;

$t=\dfrac{(\bar{x}_{2}-\bar{x}_{1})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}+\dfrac{s _{2}^{2}}{n_{2}}}}$

$t-statistic=\dfrac{(109.1-94.5)}{\sqrt{\dfrac{10^{2} }{10}+\dfrac{9^{2}}{10}}} \approx 3.43173361147$

The two sample t-statistic ≈ 3.43

b. 3.43

Part C

From the t-table, the p-value, we have, the p-value < 0.01

a. P-value < 0.01

Part D

Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis

b. There is sufficient evidence to reject the null hypothesis.

4 0

2 years ago