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damaskus [11]
3 years ago
14

It is not possible to prove one pair of triangles congruent and then use their congruent corresponding parts to prove another pa

ir congruent. True or false
Mathematics
2 answers:
Digiron [165]3 years ago
8 0

Answer:

TRUE

Step-by-step explanation:

Go to khan academy. It will explain it well.

borishaifa [10]3 years ago
4 0

Answer:

true

The wording does not quite mean anything,

but what I think was meant to ask is

"if we use some parts of two triangles to prove they are congruent,

can we then use that to prove that

a pair of corresponding parts not used before are congruent?"

The answer is

Yes, of course,

Corresponding Parts of Congruent Triangles are Congruent,

which teachers usually abbreviate as CPCTC.

For example, if we find that

side AB is congruent with side DE,

side BC is congruent with side EF, and

angle ABC is congruent with angle DEF,

we can prove that triangles ABC and DEF are congruent

by Side-Angle-Side (SAS) congruence.

We then, by CPCTC, can conclude that other pairs of corresponding parts are congruent:

side AB is congruent with side DE,

angle BCA is congruent with angle EFD, and

angle CAB is congruent with angle FDE.

It was possible (by CPCTC) to prove those last 3 congruence statements,

after proving the triangles congruent.

The expected answer is FALSE.

Step-by-step explanation:

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Two percent of all seniors in a class of 50 have scored above 96% on an ext exam, which of the following is the number of senior
dalvyx [7]

Answer:

The number of seniors who scored above 96% is 1.

Step-by-step explanation:

Consider the provided information.

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.

Now we need to find the number of seniors who scored above 96%

For this we need to find the two percent of 50.

2% of 50 can be calculated as:

\frac{2}{100}\times50

\frac{100}{100}

1

Hence, the number of seniors who scored above 96% is 1.

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The answer to this problem is
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MissTica

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Step-by-step explanation:

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