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ioda
3 years ago
9

What is 33(4/6)+43/4

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
(132 + 198) + 10.75
how i got my answer:
33 x 4 = 132
33 x 6 = 198
and 43 divided by 4 = 10.75
i hope this helps! (if not lmk and i’ll help more)
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Find S^20 if the series 1 + 1.1 ..... is a (a) arithmetic (b) geometric
quester [9]
I'm guessing S^20 is actually referring to the 20th partial sum S_{20}, with

S_{20}=1+(1+1\times0.1)+(1+2\times0.1)+\cdots+(1+18\times0.1)+(1+19\times0.1)

in the arithmetic case, and

S_{20}=1+1.1+1.1^2+\cdots+1.1^{18}+1.1^{19}

in the geometric case.

(a) Combining like terms, we have

S_{20}=20+0.1(1+2+\cdots+18+19)

and invoking the formula

1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2

we end up with

S_{20}=20+0.1\dfrac{19\times20}2=39

(b) Multiply S_{20} by 1.1, then subtract this from S_{20}:

1.1S_{20}=1.1+1.1^2+1.1^3+\cdots+1.1^{19}+1.1^{20}

S_{20}-1.1S_{20}=-0.1S_{20}=1-1.1^{20}
\implies S_{20}=\dfrac{1.1^{20}-1}{0.1}\approx57.275
7 0
3 years ago
Factor completely h^3+2h^2-9h-18
guapka [62]

Step 1: Group this into two groups:

    h^3 + 2h^2-9h-18=(h^3 + 2h^2)+(-9h-18)

When you  do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.

Step 2: Factor out the GCF from both individual groups:

    (h^3 + 2h^2)+(-9h-18) = h^2 (h+2) -9(h+2)

Step 3: Notice both groups have that (h+2)?  That's a new GCF between the two groups, so factor that out:

    h^2 (h+2) -9(h+2) = (h+2)(h^2-9)

Step 4: That (h^2-9) piece can be factored further, since it's a difference of squares:

    (h+2)(h^2-9) = (h+2)(h+3)(h-3)

Now it's factored.

8 0
2 years ago
In a basketball game Fintan made 16 baskets. Each of the baskets is worth either 2 or 3
jekas [21]
Let x represent a 2-point basket, and y represent a 3-point basket.

Basket equation: x + y = 16
Point equation 2x + 3y = 39

Solve using system of equations:
if x + y = 16, then x = 16 - y

Plug into the second equation:
2(16-y) + 3y = 39
32 - 2y + 3y = 39
32 + y = 39
y = 7

So the number of 3-point baskets scored was 7. Hope this helps, let me know if there’s a step you don’t understand! :)
8 0
3 years ago
Above is a table with missing terms. Come up with a possible common difference that makes sense and list the missing terms.
Rina8888 [55]

Answer:

common ratio:2 2. 18  3.36  4.72 equation: 4.5(2^x)

Step-by-step explanation:

144=2*2*2*2*3*3    9=3*3

the common ratio would be 2

2. 9*2=18

3. 18*2=36

4. 36*2=72

(check) 72*2=144

0. 9/2=4.5

equation: 4.5(2^x)

7 0
3 years ago
According to national data, 5.1% of burglaries are cleared with arrests. A new detective is assigned to six different burglaries
blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5.1% of burglaries are cleared with arrests.

This means that p = 0.051

A new detective is assigned to six different burglaries.

This means that n = 6

What is the probability that at least one of them is cleared with an arrest?

Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1)

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695

26.95% probability that at least one of them is cleared with an arrest

8 0
3 years ago
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