Question

Please help. what is the quotient of 4m^12/x-1÷x^2/8m^3 assume x ≠ 0 and m≠0

Answer 1

Answer:

$\frac{32m^{15}}{x^3-x^2}$

Step-by-step explanation:

The given expression is: $\frac{4m^{12}}{x-1}\div \frac{x^2}{8m^3}$

We multiply by the reciprocal of the second fraction:

$\frac{4m^{12}}{x-1}\times \frac{8m^3}{x^2}$

We cancel out the common factors to get;

$\frac{32m^{12+3}}{x^2(x-1)}$, where $x\ne0$ and $m\ne0$

We simplify to get:

$\frac{32m^{15}}{x^3-x^2}$