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lbvjy [14]
3 years ago
10

Please help. what is the quotient of 4m^12/x-1÷x^2/8m^3 assume x ≠ 0 and m≠0

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

\frac{32m^{15}}{x^3-x^2}

Step-by-step explanation:

The given expression is: \frac{4m^{12}}{x-1}\div \frac{x^2}{8m^3}

We multiply by the reciprocal of the second fraction:

\frac{4m^{12}}{x-1}\times \frac{8m^3}{x^2}

We cancel out the common factors to get;

\frac{32m^{12+3}}{x^2(x-1)}, where x\ne0 and m\ne0

We simplify to get:

\frac{32m^{15}}{x^3-x^2}

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