$A=A_o\cdot e^{kt}\\\\\bullet A_o\text{ is the initial population}\\\bullet \text{k is the rate of decrease}\\\bullet \text{t is the number of years after 2010}\\\\A=22,000\cdot e{(-0.021)(5)}\\.\ =22,000\cdot e^{-0.105}\\.\ =19,807$

6 0

3 years ago

David and Amanda are trying to figure out how long they can live off their $12,350 savings if they spend $240 each month. They h

Romashka [77]

David's : y = 12,350 - (240x)
Amanda's : y = 12,350 + (240x)

David's equation is correct, because their spending will be multiplied by the number of months and then subtracted from their savings

7 0

3 years ago

Read 2 more answers

What is the range of the function f(x)=5x+4 when the domain is {-2,3,5}?

jonny [76]

Answer:

f (-2)=5×-2+4

= -10+4

= -6

f (3)=5×3+4

=15+4

=19

f (5)=5×5+4

25+4

=29

7 0

3 years ago