All categories

3 years ago

What does m equal in this equation? 5m+2(m+1)=23

Mathematics

2 answers:

barxatty [35]3 years ago

8 0

5m+2m+2 = 23
7m=21 , So:: m=21:7
m=3

Leviafan [203]3 years ago

6 0

The answer is m=3. 5m+2(m+1)=23 then 5m+2m+2=23 then 7m+2=23 thennn 7m=23-2 and then 7m=21 answer: m=3

You might be interested in

10 POINTS<br> Find x. Assume that segments that appear tangent are tangent.

mixas84 [53]

Answer:

Step-by-step explanation:

see explanation, use tangent property to solve question

4 0

3 years ago

If the mass of a proton is 2.53 x 10^-37 gram, what is the mass of 1,000 protons

Dmitrij [34]

We can solve this problem by the rule of three.

1000 protons=10³ protons

1 proton------------------2.53*10⁻³⁷g
10³ protons---------- x

x=(10³ protons * 2.53*10⁻³⁷) / 1 proton=2.53*10⁻³⁷⁺³ protons=
=2.53*10⁻³⁴ protons

answer: 2.53*10⁻³⁴ protons

3 0

3 years ago

Bella earned the federal minimum wage in the year 2008. During that time, she worked 37.5 hours per week. How much money did she

Mariana [72]

Answer:

Belle's weekly earnings per week in 2008: $245.7

Step-by-step explanation:

The federal minimum wage in the year 2008 was: $6.55

She worked 37.5 hours per week.

She earn each week:

$weekly earnings = 6.55*37.5=245.7$

7 0

3 years ago

Read 2 more answers

Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of

alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

- The standard form of the linear equation is Ax + BC = C, where

A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

parallel bases and which of them are the non-parallel bases

# The side RS

∵ $m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}$

# The side ST

∵ $m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}$

# The side TU

∵ $m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}$

# The side UR

∵ $m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}$

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

∵ The midpoint of RS = $(\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})$

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

midpoint of RS

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0

3 years ago

Mrs. Regan went shopping and purchased 37 trees for the yard. Mr. Regan also went shopping and bought some trees. If they ha

VikaD [51]

Answer:

45 trees

Step-by-step explanation:

82=37+M m=mr.regan

-37. -37

45=M

5 0

3 years ago