The bisector of the angle at A (call it AQ) divides the segment BC into segments BQ:QC having the ratio AB:AC. Use this fact to find x.
.. 9:15 = (2x -1):3x
.. 15(2x -1) = 9*3x . . . . . the product of the means equals the product of extremes
.. 30x -15 = 27x
.. 3x = 15
.. x = 5
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According to the value of x, the bisector AQ divides the triangle into two isosceles triangles: ABQ, ACQ.
Answer:
2(6v+13u)
Step-by-step explanation:
Factoring
B=cost per boquet
v=cost per vase
3b+5v=25.75
8b+2v=29.00
use eliminateion
divide 2nd equation by 2
4b+v=14.50
multiply it by -5 and add to other equation to eliminate v
-20b-5v=-72.5
<span><u>3b+5v=25.75 +</u></span><u />
-17b+0v=-46.75
-17b=-46.75
divide both sides by -17
b=2.75
a boquet costs $2.75
Radius^2=13, so eqn is x^2+y^2=13
Answer:
84=2l+2w
w=21
Step-by-step explanation:
84=2(l+w)
42=l+w
l=42-w
Area=l×w
A=(42-w)×w
Differentiate A=42w-w×w
with respective to "w".
dA/dw= 42-2w
For a minimum or maximum area
dA/dw=0
then, 42-2w=0
w=21
proving "A" is maximum when "w=21"
dA/dw>0 when w<21
dA/dw<0 when w>21
Therefore Area is maximum when "w=21"
