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3 years ago

Tell whether the following set is an empty set or not? A = { A quadrilateral having 3 obtuse angles}

Mathematics

2 answers:

Dovator [93]3 years ago

7 0

Answer:

No.

Step-by-step explanation:

A quadrilateral with 3 obtuse angles is possible. You could have 100°+100°+100°+60° quadrilateral or whatever. As long as it's inner angles add up to 360°, it is possible.

Step2247 [10]3 years ago

3 0

Answer:

$\boxed{\mathrm{It \: is \: not \: an \: empty \: set}}$

Step-by-step explanation:

A quadrilateral with 3 obtuse angles is possible.

A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.

Let’s say three angles are measuring 91 degrees in a quadrilateral.

91 + 91 + 91 + x = 360

x = 87

The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.

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What is the answer to 14<-8+z what is Z?

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Answer:

22 < z

Step-by-step explanation:

14<-8+z

Add 8 to each side

14+8<-8+8+z

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The median is the middle number in a sorted, ascending or descending.

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pantera1 [17]

Here we are given the specific equation of:

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m = 0.4

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Answer:

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3 years ago

Bill and Greg are walking in opposite directions with speeds of 45 and 75 feet per minute. When they started, the distance betwe

mr_godi [17]

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4 years ago

What is the simplified form of the following expression? 2√27+√12-3√3-2√12

LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$

but

$2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}$

$\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}$

Since √12=2√3,this implies that,

$2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}$

Therefore,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}$

$=(6+2-3-4)\sqrt{3}$

$=\sqrt{3}$

The simplified form of ,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$ is √3

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3 years ago