Either mean or median, they are both 14 in this data set.
-0.615
-5/8 = 0.625
-0.62
with negatives, the larger the number is, the smaller it is
-0.625 , -0.62 , -0.615....least to greatest
To find out time interval δt we need to substract initial time from the final time. In this question first number in the coordinates representes time:
δt=50 - 0
δt= 50s
TIme interval is 50s.
H/5 = tan(60°)
h = 5tan(60°)
h = 5rt(3)
~F
