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nasty-shy [4]
3 years ago
11

Seth worked 23.5 hours last week at Chick-fil-la. He earns $8.00 per hour. What were Seth’s earnings for last week?

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0

Answer:

Seth earned $188 last week

Step-by-step explanation:

23.5 hours worked last week x $8.00 per hour = $188 dollars made in 23.5 hours

Gemiola [76]3 years ago
4 0

Answer:

$188

Step-by-step explanation:

23.5x$8.00=$188.

Hope this helps. (:

<em><u>Could I please have BRAINLIEST.</u></em>

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Afina-wow [57]

Answer:

Xcm

Step-by-step explanation:

jast add x to something than put cm

7 0
3 years ago
The velocity function, in feet per second, is given for a particle moving along a straight line. Find (a) the displacement and (
AveGali [126]

Answer:

(a) 2 feet.

(b) 2 feet.

Step-by-step explanation:

We have been given that the velocity function v(t)=\frac{1}{\sqrt{t}} in feet per second, is given for a particle moving along a straight line.

(a) We are asked to find the displacement over the interval 1\leq t\leq 4.

Since velocity is derivative of position function , so to find the displacement (position shift) from the velocity function, we need to integrate the velocity function.

\int\limits^b_a {v(t)} \, dt

\int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt

\int\limits^4_1 {\frac{1}{t^{\frac{1}{2}}} \, dt

\int\limits^4_1 t^{-\frac{1}{2}} \, dt

Using power rule, we will get:

\left[\frac{t^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}}\right] ^4_1

\left[\frac{t^{\frac{1}{2}}}{\frac{1}{2}}}\right] ^4_1

\left[2t^{\frac{1}{2}}\right] ^4_1  

2(4)^{\frac{1}{2}}-2(1)^{\frac{1}{2}}=2(2)-2=4-2=2

Therefore, the total displacement on the interval  1\leq t\leq 4 would be 2 feet.

(b). For distance we need to integrate the absolute value of the velocity function.

\int\limits^b_a |{v(t)|} \, dt

\int\limits^4_1 |{\frac{1}{\sqrt{t}}}| \, dt

Since square root is not defined for negative numbers, so our integral would be \int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt.

We already figured out that the value of \int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt is 2 feet, therefore, the total distance over the interval 1\leq t\leq 4 would be 2 feet.

7 0
3 years ago
The answer to the equation​
BabaBlast [244]

Answer:

Theirs no equality

Step-by-step explanation:

.

3 0
3 years ago
Answer with Explanation please! Thank you!
skad [1K]

Answer:

D

Step-by-step explanation:

2(x+b) = ax+c

2x+2b = ax+c

c = 2b

6 0
3 years ago
F(x)=16x^4-81=0 select all zeros of the function !!!
atroni [7]

Answer:

3/2, -3/2, (if it is asking for imaginary solutions as well then 3i/2 and -3i/2)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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