Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.
Answer:2
Step-by-step explanation:
First, I would solve the second parenthesis.
(4xy^3)^2
Distribute
(4^2 x^2 y^6)
4 x 4 = 16
Now, combine like terms
3x^2 x 4x^2 = 12x^4
y^2 x y^6 = y^12
So, the answer would be 12x^4 y^12
Hmm actually I'm not sure. I did this about two years ago so I don't really remember sorry if this is really wrong
Answer:
42cm^2
Step-by-step explanation:
are u in a test ;-;
two width is 28-9*2=10
width=5
ef=trapezium height=6
traqiuzm area=(5+9)*6/2
ANSWER IS 42
