Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
Answer:
72
Step-by-step explanation:
<1 and <2 are not equal to each other
Let the angle directly above angle 2 (on the right side of the line) be angle 3
<1 and <3 are corresponding angle, which means they are equal
<2 and <3 are supplementary angles since the form a line
<2 + <3 = 180
We know <1 = <3
<1 + <3 = 180
We are given <1 = 2x+12 and <2 = 3x+18
2x+12 + 3x+18 = 180
Combine like terms
5x+30 = 180
Subtract 30 from each side
5x+30-30 = 180-30
5x= 150
Divide each side by 5
5x/5 = 150/5
x=30
<1 = 2x+12
Substitute 30 in for x to find angle 1
= 2*30 +12
=60+12
= 72
Answer:
f = 5/6
Step-by-step explanation:
5(4f + 3) - 2f
= 20f + 15 - 2f
= 18f + 15
18f = 15
f = 15/18
f = 5/6
I believe your answer is 6 seconds.
Because the height of the ball = -16(x² - 5x - 6), when the height of the ball is 0, which is when it is on the ground, we can set -16(x² - 5x - 6) equal to 0. This also allows us to divide by -16, and then we can solve the equation:
x² - 5x - 6 = 0
(x - 6)(x + 1) = 0
So x = 6 or x = -1, and because a quantity of time cannot be negative, x would have to be 6, which means it takes 6 seconds for the ball to reach 0 feet.
I hope this helps!
Answer:
The first equation must be multiplied by 18 and second equation must be multiplied by 8
Step-by-step explanation: