You would need to have the information of how it translated, wether it was left or right, or up or down. you would also want the information of how far it translated.
Answer:
120 cm²
Step-by-step explanation:
From the question;
- Length is 12 cm
- Width is 10 cm
We are required to determine the area of the cross section;
- Note that the cross section is the plane of a solid that remains constant through the solid.
- In this case, the cross section is a rectangle whose dimensions are 12 cm by 10 cm.
But Area of a rectangle = Length × Width
Therefore;
Area of cross section = 12 cm × 10 cm
= 120 cm²
Thus, area of the cross section is 120 cm²
Answer:
distribute the 5 on the right to get 15-10x=5x+45
Step-by-step explanation:
1. 5 1/2 - 1 2/3 This is the way I find easiest:-
= 11/2 - 5/3 LCD = 6 so multiply 11/2 by 3/3 and 5/3 by 2/2:-
= 33/6 - 10/6
= 23/6
= 3 5/6 Answer
Hope this helps
Mes ∠ O = mes (arc PQR/2)
mes ∠ Q = mes (arc POR/2)
arc PQR + arc POR = 360°
arc PQR/2 + arc POR/2 = 180°
THEN:
mes ∠ O + mes ∠ Q = mes(arc PQR/2) + mes(arc POR/2) = 180°
∠ O + ∠ Q = 180° are supplementary