Question

(X+2)^2+(y-4)^2=16 what is the radius

Answer 1

Answer:

The radius = 4

Step-by-step explanation:

considering the equation

$\left(x+2\right)^2+\left(y-4\right)^2=16$

As the standard form of the circle is

$\left(x-h\right)^2+\left(y-k\right)^2=r^2$

Match the values in this circle to those of the standard form.

• The variable  $r$ represents the radius of the circle,  

• $h$ represents the x-offset from the origin, and  

• $k$  represents the y-offset from origin.

$\mathrm{Rewrite}\:\left(x+2\right)^2+\left(y-4\right)^2=16\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}$

$\left(x-\left(-2\right)\right)^2+\left(y-4\right)^2=4^2$

$\mathrm{Therefore\:the\:circle\:properties\:are:}$

$\left(h,\:k\right)=\left(-2,\:4\right),\:r=4$

Therefore, the radius = 4