20x + 2y + 6 (simplified)
We have been given that
and angle A is in quadrant 1. We are asked to find the exact value of
in simplest radical form.
We know that sine relates opposite side of right triangle with hypotenuse.
![\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}](https://tex.z-dn.net/?f=%5Ctext%7Bsin%7D%3D%5Cfrac%7B%5Ctext%7BOpposite%7D%7D%7B%5Ctext%7BHypotenuse%7D%7D)
This means that opposite side is 12 units and hypotenuse is 13 units.
We know that cotangent relates adjacent side of right triangle with adjacent side.
![\text{cot}=\frac{\text{Adjacent}}{\text{Opposite}}](https://tex.z-dn.net/?f=%5Ctext%7Bcot%7D%3D%5Cfrac%7B%5Ctext%7BAdjacent%7D%7D%7B%5Ctext%7BOpposite%7D%7D)
Now we will find adjacent side using Pythagoras theorem as:
![\text{Adjacent}^2=\text{Hypotenuse}^2-\text{Oppoiste}^2](https://tex.z-dn.net/?f=%5Ctext%7BAdjacent%7D%5E2%3D%5Ctext%7BHypotenuse%7D%5E2-%5Ctext%7BOppoiste%7D%5E2)
![\text{Adjacent}^2=13^2-12^2](https://tex.z-dn.net/?f=%5Ctext%7BAdjacent%7D%5E2%3D13%5E2-12%5E2)
![\text{Adjacent}^2=169-144](https://tex.z-dn.net/?f=%5Ctext%7BAdjacent%7D%5E2%3D169-144)
![\text{Adjacent}^2=25](https://tex.z-dn.net/?f=%5Ctext%7BAdjacent%7D%5E2%3D25)
Let us take positive square root on both sides:
![\text{Adjacent}=5](https://tex.z-dn.net/?f=%5Ctext%7BAdjacent%7D%3D5)
Therefore, adjacent side of angle A is 5 units.
![\text{cot}(A)=\frac{5}{12}](https://tex.z-dn.net/?f=%5Ctext%7Bcot%7D%28A%29%3D%5Cfrac%7B5%7D%7B12%7D)
Therefore, the exact value of cot A is
.
Answer:
A) x² + 7x - 9
Step-by-step explanation:
Deduct\Add each like-term to arrive at your answer.
Answer:
![x^{\frac{2}{3} }](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
Step-by-step explanation:
⇒ ![x^({\frac{4+2}{3}) } ^{\frac{1}{3} }](https://tex.z-dn.net/?f=x%5E%28%7B%5Cfrac%7B4%2B2%7D%7B3%7D%29%20%7D%20%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
⇒ ![(x^{\frac{6}{3} })](https://tex.z-dn.net/?f=%28x%5E%7B%5Cfrac%7B6%7D%7B3%7D%20%7D%29)
⇒ ![(x^{2} )\frac{1}{3}](https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%29%5Cfrac%7B1%7D%7B3%7D)
⇒ ![x^{\frac{2}{3} }](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
Answer:
a3= -343
divade both side by 3 to make a the subject
a3/3= -343/3
a = -114.3