Complex roots occur when b^2 - 4ac is negative.
So we have (-6)^2 - 4.1.k < 0
-4k < - 36
k > 9
(3,5)....x1 = 3 and y1 = 5
(1,3)....x2 = 1 and y2 = 3
slope formula : (y2 - y1) / (x2 - x1)
slope = (3 - 5) / (1 - 3) = -2/-2 = 1 <== slope is 1
Px+qx+py+qy=0
X (p+q)+y(p+q)=0
(p+q) (x+y)=0
Hope this helps! Have a good day/night!!
Answer & Step-by-step explanation:
1) 4x
2) y-8
3) 6/x
4) 12-y
5) y+9
6) 5^2
7) x^4
8) 9+n
9) 64-y
10) 12/n
11) x^2/7
12) x-8=22
13) 2a-b^2
14) 12-ab
Answer:
10
Step-by-step explanation:
