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4 years ago

PLZ HELP! WILL GIVE BRAINLIEST TEN POINTS

Mathematics

2 answers:

dexar [7]4 years ago

8 0

Answer:

48,200 hours

Tatiana [17]4 years ago

3 0

Answer:

Time = distance/speed. T = 1,200,000,000/28,000. This can be cancelled to 1,200,000/28. Rounding 28 to 30 for the estimate, divide by another ten: 120,000. Then divide by the remaining 3 from 30: 120,000/3 = 40,000. It will take approximately 40,000 hours.

<em>Hope This Helps!</em>

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Iron-59 has a half-life of 44.5 days. How much of a 3.00 mg sample will be left after 222.5 days?

rusak2 [61]

Answer: D. About 0.09 milligrams

Step-by-step explanation:

I took the quiz and got it right!

5 0

3 years ago

Worth 25 points, giving brainiest to a quick and good answer.

vredina [299]

Answer:

Step-by-step explanation:

Note that the quadratic formula has that "plus or minus" due to our taking the square root of some quantity. No square root is involved in the two formulas you've posed.

I have two suggestions here:

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7 0

3 years ago

Solve the system below using any method:<br> X+2y=1<br> 5x-4y=-23

DaniilM [7]

X+2y=1
2y =1-x
y= (1-x)/2

5x-4y= -23
By substituting the value of y in this equation
5x -4 {(1-2)/2} = -23
5x- 2 +2x = -23
7x= -21
x= -3

Now, let's find the value of y bu putting the value in any othe two equations
I'll use x +2y=1
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6 0

3 years ago

Read 2 more answers

A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with t

erik [133]

Answer:

a) P=0.2

b) P=0.42

c) P=0.7

d) Marginal probability distribution of x:

$p_x(0)=p(0,0)+p(0,1)+p(0,2)=0.10+0.04+0.02=0.16\\\\p_x(1)=p(1,0)+p(1,1)+p(1,2)=0.08+0.2+0.06=0.34\\\\p_x(2)=p(2,0)+p(2,1)+p(2,2)=0.06+0.14+0.30=0.50$

Marginal probability distribution of y:

$p_y(0)=p(0,0)+p(1,0)+p(2,0)=0.10+0.08+0.06=0.24\\\\p_y(1)=p(0,1)+p(1,1)+p(2,1)=0.04+0.2+0.14=0.38\\\\p_y(2)=p(0,2)+p(1,2)+p(2,2)=0.02+0.06+0.3=0.38$

e) The two variables are dependant.

Step-by-step explanation:

The joint pmf of X and Y appears in the accompanying tabulation (attached).

a) Is the proability that one hose being used in the self service island and one hose being use in the full service island.

$P(X=1 \& Y=1)=P(1,1)=0.2$

(according to the tabulation)

$P(X\leq1 \& Y\leq1)=P(0,0)+P(1,0)+P(0,1)+P(1,1)\\\\P(X\leq1 \& Y\leq1)=0.10+0.08+0.04+0.20\\\\P(X\leq1 \& Y\leq1)=0.42$

c) This event means that at least one hose is in use in each of the island.

$P(X\neq0 \& Y\neq0)=P(1,1)+P(1,2)+P(2,1)+P(2,2)\\\\P(X\neq0 \& Y\neq0)=0.20+0.06+0.14+0.30=0.70$

Marginal probability distribution of x:

$p_x(0)=p(0,0)+p(0,1)+p(0,2)=0.10+0.04+0.02=0.16\\\\p_x(1)=p(1,0)+p(1,1)+p(1,2)=0.08+0.2+0.06=0.34\\\\p_x(2)=p(2,0)+p(2,1)+p(2,2)=0.06+0.14+0.30=0.50$

Marginal probability distribution of y:

$p_y(0)=p(0,0)+p(1,0)+p(2,0)=0.10+0.08+0.06=0.24\\\\p_y(1)=p(0,1)+p(1,1)+p(2,1)=0.04+0.2+0.14=0.38\\\\p_y(2)=p(0,2)+p(1,2)+p(2,2)=0.02+0.06+0.3=0.38$

Compute P(X≤1)

$P(X\leq1)=p_x(0)+p_x(1)=0.16+0.34=0.50$

e) For X and Y to be independent variables, the following conditions must be true:

P(x|y) = P(x), for all values of X and Y.

P(x ∩ y) = P(x) * P(y), for all values of X and Y.

We evaluate the second probability for X=1 and Y=1.

$P(x=1 \cap y=1) = 0.2\\\\p_x(1)*p_y(1)=0.34*0.38=0.1292\\\\\\P(x=1 \cap y=1)\neq p_x(1)*p_y(1)$

This condition is not satisfied, so the two variables are dependant.

4 0

3 years ago

Question 5 (1 point)

dexar [7]

Answer:

4.5

Step-by-step explanation:

8 + 7 + 6 + 5 + 4 + 3 + 2 + 1/8

36/8

=4.5

3 0

3 years ago