All categories

3 years ago

PLZ HELP! WILL GIVE BRAINLIEST TEN POINTS

Mathematics

2 answers:

dexar [7]3 years ago

8 0

Answer:

48,200 hours

Tatiana [17]3 years ago

3 0

Answer:

Time = distance/speed. T = 1,200,000,000/28,000. This can be cancelled to 1,200,000/28. Rounding 28 to 30 for the estimate, divide by another ten: 120,000. Then divide by the remaining 3 from 30: 120,000/3 = 40,000. It will take approximately 40,000 hours.

<em>Hope This Helps!</em>

You might be interested in

a cross section of a parabolic glass mirror of the Hubble space telescope shown can be modeled by the graph of the function y=0.

PilotLPTM [1.2K]

You need to divide this one :)

Hope this helps

8 0

3 years ago

Find the value of x so that the polygons have the same perimeter.

Novosadov [1.4K]

Answer: x=4

Step-by-step explanation:

The perimeter´s formula for this kind of polygons is

The triangle perimeter would be:

(x+2)+(x+3)+(x+3)

And the rectangle:

(x+2)+(x+2)+x+x

For them to have the same value, we should equal them:

(x+2)+(x+3)+(x+3)=(x+2)+(x+2)+x+x

Working with this:

3x+8=4x+4

x=4

4 0

2 years ago

The system of equations has 2x-y=2(x+1) y=-2

sleet_krkn [62]

Answer:

Step-by-step explanation:

This equation has no solution.

3 0

2 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

2 years ago

I will mark as the brainiest if you get this correct<br> thx so much xxx

fgiga [73]

360 g plain flour
3 eggs
900 ml milk

4 0

3 years ago