Answer:
0.79 ; 0.753
Step-by-step explanation:
Given that:
Students who have spent at least five hours studying GMAT review guides have a probability of 0.85 of scoring above 400 :
≥ 5 hours review = 0.85
Students who do not spend at least five hours reviewing have a probability of 0.65 of scoring above 400
< 5 hours = 0.65
70% (0.7) of business students spend atleast 5 hours review time
A.) probability of scoring above 400
(Proportion who spend atleast 5 hours review time * 0.85) + (Proportion who do not spend atleast 5 hours * 0.65)
Proportion who do not spend atleast 5 hours = (1 - proportion who spend atleast 5 hours) = 1 - 0.7 = 0.3
Hence,
P(scoring above 400) = (0.7 * 0.85) + (0.3 * 0.65) = 0.595 + 0.195
= 0.79
B.) probability that given a student scored above 400, he/she spent at least five hours reviewing for the test.
P(spent ≥5 hours review | score above 400) :
P(spent ≥5 hours review) / P(score > 400)
(0.7 * 0.85) / 0.79
0.595 / 0.79
= 0.753
Answer:
The median is 83.
Step-by-step explanation:
What best describes the range of possible values for the third side of the triangle are
- If the 3rd side is less than 6, it could never reach between the ends of the 10 and the 16.
- If the 3rd side is more than 26, then the 10 and the 26 could never reach its ends.
This is further explained below.
<h3>What is the range?</h3>
Generally, After removing the sample maximum and lowest, we get the range of the data set. It shares the same measurement systems as the data.
In conclusion, Choose the options that best characterize the interval across which the third side may take on a value;
When the 10 and 16 are placed end to end, the third side can never be shorter than 6.
If the sum of the 10 and the 26 is more than the third side's value, then the 10 and the 26 will never sum to the side's value.
Read more about the range
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For a direct variation, f(x) = kx. Therefore, for f(x) = 30x, constant of variation (k) = 30.
4/13 because the absolute value would be itself since it is positive. If it was negative then the absolute value would be positive.
