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NNADVOKAT [17]
3 years ago
6

What is the product?

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
-9 -8
2. 0



Just multiply
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Mia had $22. Then she started to receive $4 a week as an allowance. She plans to save all of her money for a bicycle and draws a
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first y then x because y represents 22 and x represents 4 a week.

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3 years ago
If a batch of cookies uses
lianna [129]

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13 1/3 cups of sugar

Step-by-step explanation:

8 0
3 years ago
How to solve for X: X-B=A
mamaluj [8]

Answer:

Step-by-step explanation:

(x−a)(x−b)=x2−(a+b)x+ab

Now, this with the third bracket.

(x2−(a+b)x+ab)(x−c)=x3−(a+b+c)x2+(ac+bc+ab)x−abc

But there’s another way to do this, which is easier. Assume the given expression is equal to 0, then, we can form a cubic equation as

x3−(sum−of−roots)x2+(product−of−roots−taken−two−at−a−time)x−(product−of−roots) , which is essentially what we got above.

5 0
3 years ago
Read 2 more answers
Dale finished his English assignment in 1/3 hours . Then he completed his chemistry assignment in 1/2 hours . How much more time
11Alexandr11 [23.1K]

Answer:

1/6 hours

Step-by-step explanation:

Since it wants a fraction form all you have to do is subract 1/3 from 1/2

1/2 - 1/3

cross multiply:

3/2-2/3

subtract the numerator but multiply the denominator and simplify if you have to:

1/6

6 0
3 years ago
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
2 years ago
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