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Musya8 [376]
2 years ago
7

8X 1 + 5 X 1/100 + 9 X 1/1000

Mathematics
2 answers:
USPshnik [31]2 years ago
7 0
I hope this helps you

tresset_1 [31]2 years ago
6 0
8

8*1+5*1/100+9*1/1000=8.059









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If varies inversely as . It is known that = 10 when = 3, find the value of when = 5.
Leto [7]

Answer:

y = 6

Step-by-step explanation:

If x varies inversely proportional as y.

x=\dfrac{k}{y}, k is constant of proportionality

or

k = xy

When x = 3 and y = 10

k = 3×10

k = 30

Put x = 5,

y=\dfrac{k}{x}\\\\y=\dfrac{30}{5}\\\\y=6

So, the value of y is 6 when x is 5.

8 0
2 years ago
Here's the png with the question. I think I have the right answer but I need help.
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Answer:

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Step-by-step explanation:

8 0
2 years ago
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Factor: 81y^2-49<br> Your answer
oksian1 [2.3K]

Answer:(9y-7)(9y+7)

Step-by-step explanation:

81y^2-49

=(9y)^2-(7)^2

=(9y-7)(9y+7)

4 0
2 years ago
Write the contrapositive of the conditional statement. If a shape is a rhombus, then it has four congruent sides.
NikAS [45]
If the figure does not have four congruent sides, then the shape is not a rhombus.
7 0
2 years ago
The amount of $15,000 is invested in two funds paying 2% and 5% simple interest. If the annual interest is $540, how much of the
Lostsunrise [7]

Answer:

The amount $15000 is divided as

in 2% = $7000

in 5% = $8000

Step-by-step explanation:

It is given that the total amount is $15000 and rates of interests are 2% and 5%.

<em>Let the amount invested in 2% be "x", so the amount invested in 5% is (15000 - x).</em>

The annual interest on x part is given as,

= (\frac{2}{100})(x)

Similarly, The annual interest on (15000 - x) part is given as,

=  (\frac{5}{100})(15000 - x)

the total annual interest is given as $540

Thus, <em>540 = (\frac{5}{100})(15000 - x) + (\frac{2}{100})(x)</em>

<em>54000 = 2(x) + 75000 - 5(x)</em>

<em>21000 = 3(x)</em>

x = \frac{21000}{3} = 7000

Thus the shares are $7000 and (15000 - 7000) $8000 .

8 0
2 years ago
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