Answer:
Explanation:
The following code is written in Java and uses a for loop with a series of IF ELSE statements to check the next and previous characters in a string. Checking to make sure that there are no asterix. If so it adds that character to the String variable output. Which is returned to the user at the end of the method. Two test cases have been created and the output can be seen in the attached image below.
class Brainly {
public static void main(String[] args) {
System.out.println(starOut("sm*eilly"));
System.out.println(starOut("ab**cd"));
}
public static String starOut(String str) {
String output = "";
for (int i = 0; i < str.length(); i++) {
if ((i != 0) && (i != str.length()-1)) {
if ((str.charAt(i-1) != '*') && (str.charAt(i+1) != '*') && (str.charAt(i) != '*')) {
output += str.charAt(i);
}
} else {
if ((i == 0) && (str.charAt(i) != '*') && (str.charAt(i+1) != '*')) {
output += str.charAt(i);
} else if ((i == str.length()-1) && (str.charAt(i) != '*') && (str.charAt(i-1) != '*')) {
output += str.charAt(i);
}
}
}
return output;
}
}
Answer:
first question option is d
second is false
third is mark
Explanation:
5-The following are generic font
- serif
- sans-serif
- cursive
- fantasy
- monospace
6 - We can change image size using height and width. so it is false.
7 - we can highlight text using <mark> Marked text </mark>
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image