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Sveta_85 [38]
3 years ago
8

I need help with this problem

Biology
1 answer:
rosijanka [135]3 years ago
6 0
What is the problem?
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A man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was six
Degger [83]

Answer:

1/4.

Explanation:

The autosomal dominant trait means that the trait is visible in homozygous dominant and in heterozygous condition. The X linked recessive trait will be pass down from mothers to their sons and daughters will show the trait in homozygous recessive condition only.

The man is achandroplastic dwarf ( Aa) with normal vision (XY ) is married with woman that has normal height (aa) with color blind (XhXh). They have a daughter who is dwarf ( Aa). The probability of being dwarf can be calculated by the cross Aa × aa. The offspring are Aa, Aa, aa, aa. Means 1/2 are the probability of being hetterozygous for achondroplastic . The vision probability is calculated by cross XY and XhXHh. The probability that female is heterozygous is 1/2.

So, the heterozygous probability for both trait is 1/2× 1/2 = 1/4.

3 0
4 years ago
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