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4 years ago

[(3 + 2)²×2] -(6-3)²

Mathematics

2 answers:

Ulleksa [173]4 years ago

7 0

Answer:

Step-by-step explanation:

Oksana_A [137]4 years ago

6 0

Answer:

41 is your final answer.

Step-by-step explanation:

For order od operations, you need to remember BPEMDAS. This stands for Brackets, Perenthesis, Exponents, Multiplication or Division, and Addition or Subtraction. This is the order of which you will complete the prolem, starting with Brackets.

1. Start off by solving with whats inside the brackets.

(3 + 2)²×2

And specifically inside the perenthesis.

(3 + 2) = 5

(5)²×2

Now the exponent(s).

(5)² = 25

25×2

now solve.

25×2 = 50

Your new equation is: 50 -(6-3)²

2. Again we go in order, starting this peice with perenthesis.

(6-3) = 3

50 -3²

Now the exponent(s).

3² = 9

50 -9

And finally subtract!

50 -9 = 41

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3 years ago

An airplane is flying from New York City to Los Angeles the distance it travels in Miles D is related to the time in seconds T b

tatiyna

Answer:

It takes 85 seconds to go 12.75 miles

Step-by-step explanation:

We are given

An airplane is flying from New York City to Los Angeles

the distance it travels in Miles D is related to the time in seconds T by the equation

$d=0.15T$

we are given to find time when distance is 12.75 miles

so, we can set d=12.75

and then we can solve for T

$12.75=0.15T$

We can divide both sides by 0.15

$T=\frac{12.75}{0.15}$

$T=85$

So,

It takes 85 seconds to go 12.75 miles

6 0

3 years ago

Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle

Whitepunk [10]

Answer:

$(6\sqrt{3},\,\frac{5\pi}{6})$

Step-by-step explanation:

The radius r can be found from the relationship

$r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}$

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

$\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}$