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katrin [286]
3 years ago
11

A circle is centered at (2, -5) and has radius 3. Write its equation in standard form. A) (x + 2)2 + (y - 5)2 = 3 B) (x - 2)2 +

(y + 5)2 = 3 Eliminate C) (x + 2)2 + (y - 5)2 = 9 D) (x - 2)2 + (y + 5)2 = 9
Mathematics
2 answers:
ozzi3 years ago
7 0
I think its D because the radius must be squares and 5 must be added because thats the same as subtracting a negative
ki77a [65]3 years ago
4 0
D.
(x - h)^{2}  +  {(y - k)}^{2}  = r^{2}
Where (h, k) is the center of the circle and the radius is squared.
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