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givi [52]
3 years ago
12

Use the discriminant to find the number of real roots in Y = x^2 – 6x + 9

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0
So discriminant is being counted from that equation:
b^2-4ac = 36-36 = 0

As discriminant is 0, then there is just 1 root -> -b/2a = 6/2 = 3.
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Step-by-step explanation:

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KengaRu [80]
<span>(1,625) No (0,-25) No (-1,-1) No Think about what an integer exponent means for an negative base and you'll understand this problem. For instance the powers of -25 would be -25^1 = -25 -25^2 = (-25) * (-25) = 625 -25^3 = (-25)*(-25)*(-25) = -15625 and so on, giving 390625, -9765625, 244140625, etc. But that's a different subject. For the ordered pairs given, let's check them out. (1,625) -25^1 + 1 = -25 + 1 = -24. And -24 is not equal to 625, so "No". (0,-25) -25^0 + 1 = 1 +1 = 2. Note: Any real number other than 0 raised to the 0th power is 1. And 2 is not equal to -25, so "No". (-1,-1) -25^(-1) + 1 = 1/(-25^1) + 1 = 1/-25 + 1 = 24/25. And 24/25 is not equal to -1, so also "No".</span>
3 0
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Hope this helps :)
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2 years ago
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Answer:

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Hope this helps :)

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