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3 years ago

Which of the following cannot be used in proving triangles congruence

Mathematics

2 answers:

iragen [17]3 years ago

8 0

I can not see the problem.

Margarita [4]3 years ago

5 0

SSA Postulate; this postulate is not a theorem.

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a cook needs 12 pounds of flour he wants to spend the least amount of money if a 2 pound bag costs $1.59 and a 5 pound bag costs

Virty [35]

He should buy two 5 pound bags and one 2 pound bag.

4 0

3 years ago

Read 2 more answers

What is the difference between (Picture 1) and (picture 2)? A. 0 B. 2 C. 5 D. 6

Vesnalui [34]

Answer:

The difference between the picture is 0 , option A .

Step-by-step explanation:

Given two figures as :

In figure A

The expression is 1 + 3 n , where n lies from 0 to 4

So , let f (n) = 1 + 3 n

Or,f ( n ) = 1 + 3 ×0 = 1 + 0 = 1

f ( 1 ) = 1 + 3 ×1 = 1+ 3 = 4

f ( 2 ) = 1 + 3 ×2 = 1+ 6 = 7

f ( 3 ) = 1 + 3 ×3 = 1+ 9 = 10

f ( 4 ) = 1 + 3 ×4 = 1+ 12 = 13

so, summation of ( 1 + 3 n ) from n = 0 to 4 = 1 + 4 + 7 + 10 + 13 = 35

In figure B

The expression is 3 i - 5 , where i lies from 2 to 6

So , let g (i) = 3 i - 5

Or,g ( 2 ) = 3 ×2 - 5 = 6 - 5 = 1

g ( 3 ) = 3 ×3 - 5 = 9 - 5 = 4

g ( 4 ) = 3 ×4 - 5 = 12 - 5 = 7

f ( 5 ) = 3 ×5 - 5 = 15 - 5 = 10

f ( 6 ) = 3 ×6 - 5 = 18 - 5 = 13

so, summation of ( 3 i - 5 ) from i = 2 to 6 = 1 + 4 + 7 + 10 + 13 = 35

So, The difference between the summation of functions f(n) - g(i) is

f(n) - g(i) = 35 - 35

I.e f(n) - g(i) = 0

Hence The difference between the picture is 0 , option A . Answer

4 0

3 years ago

In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th

MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

$\frac{20!}{18!2!}=190$

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0

3 years ago

Which of the following represents 4x^5/6 in radical form

mash [69]

Remember, order of operations
exponent before multiply

so 4x^5/6=4 times x^5/6
simplify the x^5/6 first

remember
$x^\frac{m}{n}=\sqrt[n]{s^m}$

so
$x^\frac{5}{6}=\sqrt[6]{x^5}$

so
$4x^\frac{5}{6}=4\sqrt[6]{x^5}$
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6 0

3 years ago

60points if you answer

Anton [14]

-4 > -5, -4 is > or equal to 5

7 0

2 years ago

Read 2 more answers