Answer:
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Answer:
Let the distance between woman and pole be "x".
From diagram,
In ΔOAB,
tan 18 =
tan 18 =
∴ x = ................ (1)
In ΔOBC
tan 14 =
tan 14 =
y = x × tan 14 ..............(2)
equating (2) in (1), we get;
x =
x =
∵ tan 18 + tan 14 = 0.574
<em>∴ x = 113.2 ft</em>
<em>i.e. The her distance from the pole is 113.2 ft.</em>
