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Ainat [17]
3 years ago
7

Helppppp plsssssss help

Mathematics
1 answer:
slava [35]3 years ago
4 0
The answer is C. P=h + 11
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The first shipping by company charges a fee of $20 to ship a medium box, plus an additional $1 per pound. A second company charg
viktelen [127]

Answer:

Total cost=$25

Step-by-step explanation:

We can derive two expressions as follows;

Total cost for the First shipping company=Medium box charges+total additional charges

where;

Medium box charges=$20

Total additional charges=Charges per pound×number of additional pounds (n)

Total additional charges=1×n=n

replacing;

Total cost for the First shipping company=20+n....equation 1

Total cost for the second shipping company=Medium box charges+total additional charges

where;

Medium box charges=$15

Total additional charges=Charges per pound×number of additional pounds (n)

Total additional charges=2×n=2 n

replacing;

Total cost for the First shipping company=15+2 n....equation 2

Equating equation 1 and equation 2

15+2 n=20+n

2 n-n=20-15

n=5

Replace the value for n in equation 2

Total cost for the First shipping company=15+2 n....equation 2

Total cost=15+(2×5)=$25

7 0
3 years ago
What does n equal to in 12n + 9 = 6 - 3n
sveticcg [70]
12n+9=6-3n\ \ \ \ \ \ |Add\ 3n\ to\ each\ side\\\\
15n+9=6\ \ \ \ \ |Subtract\ 9\\\\
15n=-3\ \ \ \ \ |Divide\ by\ -15\\\\
n=-\frac{3}{15}=\boxed{-\frac{1}{5}}
6 0
3 years ago
Does anybody have any tips for calculating slopes in Algebra 1???
I am Lyosha [343]

Answer:

The equations are really hard, so if you can find a slope interpreter or something that might be helpful.

I find it easier to just count the up and across.

Step-by-step explanation:

6 0
3 years ago
Help!! I need an answer asap!! <br><br> Given a∥b, find m∠1 = 71º. <br> Find: m∠5, m∠8
Sindrei [870]

Answer:

m<5 = 71 and m<8 = 109

Step-by-step explanation:

m<1 is equivalent to m<5 and m<2 is equivalent to m<8.

5 0
2 years ago
Read 2 more answers
X/5=2/3=5/y<br><br> 2/3 <br> 4/9<br> 1
Mademuasel [1]
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
Break the equation into parts;
\frac{x}{5} = \frac{2}{3} ;  \frac{2}{3}= \frac{5}{y}
Solving for x;
\frac{x}{5} = \frac{2}{3}
x=\frac{10}{3}
Solving for y;
\frac{2}{3} = \frac{5}{y} &#10;y= \frac{3*5}{2} &#10;y= \frac{15}{2}
\frac{x}{y} = \frac{10/3}{15/2}
\frac{x}{y} = \frac{4}{15}
5 0
3 years ago
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