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steposvetlana [31]
4 years ago
10

Henrietta has a box of fruit with a mass of 88 dekagrams. What is the weight of the box of fruit in kilograms?

Mathematics
2 answers:
garri49 [273]4 years ago
8 0
The answer is A)0.88 kilograms
Elenna [48]4 years ago
6 0
It’s A
Step-by-step-explanation
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What is the equation to (-3,1) and (0,-8)
puteri [66]
The change in x between the two is 3 and the change in y is -9. 
Divide -9 by 3 to get -3 using the rise over run slope formula.  
The equation is y = -8 + -3x because the -8 in the second set of coordinates is the y-intercept of the equation. 
Hope this helps!
4 0
3 years ago
Find the sum of the first 100 terms of the sequence below:<br> -19, -15, -11, -7, -3, ...<br> S100
ch4aika [34]

Answer:

17900

Step-by-step explanation:

First term a = -19

common difference d = -15-(-19) = 4

number of terms, n = 100

sum of first 100 terms,

n/2(2a+(n-1)d)

= 100/2(2×(-19)+(100-1)4)

= 50×(-38+99×4)

= 50×358

= 17900

5 0
3 years ago
What is the first step needed to solve 3 over 4 multiplied by x minus 3 equals negative 18?
NemiM [27]
My answer would be to add 3 to both sides
8 0
3 years ago
How many ways can Hannah give three of her eight T-shirts to her younger sister?
prisoha [69]
If Hannah gives her younger sister 3 shirts, it does not matter what order she hands them to her. No matter the order, it will still be the same group of 3 shirt. Since order is not important this problem can be solved using a combination.

Specifically we are asked to find 8C3 (sometimes called "8 choose 3"). This is a fraction. In the numerator we start with 8 and count down 3 numbers. In the denominator we start with 3 and count all the way down to 1. Thus we obtain,

\frac{(8)(7)(6)}{(3)(2)(1)}=(8)(7)=56
7 0
3 years ago
Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas
lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

n(S) = n(s) + n(S \cap F)

In which n(s) are those who are succeful but not freshmen and n(S \cap F) are those who are succesful and freshmen.

By the same logic, we also have that:

n(F) = n(f) + n(S \cap F)

The union is:

n(S \cup F) = n(s) + n(f) + n(S \cap F)

In which

n(S \cup F) = 58

n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)

n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)

So

n(S \cup F) = n(s) + n(f) + n(S \cap F)

58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)

n(S \cap F) = 24

So the correct answer is:

b) 24

3 0
4 years ago
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