Answer:
(1,5)
Step-by-step explanation:
y = 4x+1
y = 2x+3
Set the two equations equal
4x+1 = 2x+3
Subtract 2x from each side
4x+1-2x = 2x+3-2x
2x+1 = 3
Subtract 1 from each side
2x+1-1 =3-1
2x=2
Divide by 2
2x/2 =2/2
x =1
Now find y
y =4x+1 = 4(1)+1 =4+1=5
(1,5)
Answer:
The distance between A and D to the nearest tenth is;

Explanation:
Given the two points;

Applying the distance between two points formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
substituting the given coordinates we have;
![\begin{gathered} AD=\sqrt[]{(-3-6)^2+(-2-2)^2} \\ AD=\sqrt[]{(-9)^2+(-4)^2} \\ AD=\sqrt[]{81+16} \\ AD=\sqrt[]{97} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20AD%3D%5Csqrt%5B%5D%7B%28-3-6%29%5E2%2B%28-2-2%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B%28-9%29%5E2%2B%28-4%29%5E2%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B81%2B16%7D%20%5C%5C%20AD%3D%5Csqrt%5B%5D%7B97%7D%20%5Cend%7Bgathered%7D)
Simplifying;

Therefore, the distance between A and D to the nearest tenth is;
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Answer:
your answer is c l hipe this helps u
15 1/8 -1 3/5=
15 5/40 -1 24/40=
605/40 - 64/40=
541/40= 13 21/40
Answer:13 21/40