Answer: 144.44
Step-by-step explanation:
radius is half of diameter so multiply the radius by 2 which is 46.
The circumferece of a circle is C=pi x d . multiply the rounded pi by the diameter which is 144.44
Your answers are fine.
1) Transitive property if a = b and b = c, then a = c. Replace with your letters and is is done.
2) Symmetric property of equality.
If a = b, then b = a.
The answer is 640.
32 goes into 5, 6 times.
6x5=30
32-30=2. Then you bring everything down.
And have 200, 200 goes into 5, 40times.
So, you have 640
The graph is a parabola with roots at (-4.5, 0) and (0.5, 0) and vertex at (-2, -13)
Equation using roots is a(x + 9/2)(x - 1/2) = a(x^2 + 4x - 9/4) = ax^2 + 4ax - 9/4 a . . . . . . . . (1)
Equation using vertex is a(x + 2)^2 - 13 = a(x^2 + 4x + 4) - 13 = ax^2 + 4ax + 4a - 13 . . . . . . . . (2)
From (1) and (2), -9/4 a = 4a - 13
13 = 4a + 9/4 a = 25/4 a
a = (4 x 13)/25 = 2.08 = 2 approx
Therefore required equation is y = 2x^2 + 4(2)x + 4(2) - 13 = 2x^2 + 8x + 8 - 13 = 2x^2 + 8x - 5
Answer:
Check the explanation
Step-by-step explanation:
in this particular type of problems,we have to go with the cases.we know there would be a 50 odd-even pairs between 1 and 100.
1st case: 1 is placed at the head position of given set S.so there is a chance of only one even number beside 1.so there are 50×98!
2nd case: 1 is placed at tail position of S.so there is again a chance of one even number beside 1. so there are
50×98!
3rd case: 1 is placed neither at head nor at tail.1 can be at rest 98 places.lets fix the place of 1.then the choices are difference between permuting all the numbers and 1 surrounded by two odd numbers.
i.e., 99! - 49p2 ×97!
so total choces are = 2×50×98! + 99! - 49p2 × 97!
= 7448 × 97! + 99!