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3 years ago

Alg 1 please pls help!! this is my last question for today!! which algebraic expression is a polynomial with a degree of 2?

Mathematics

1 answer:

Verdich [7]3 years ago

8 0

I don't quite understand the last answer, do you happen to have an image you can show me?

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I need help please as soon as possible

blsea [12.9K]

Answer:

a. 86-degrees; angle-2 corresponds to the given angle.

Step-by-step explanation:

Angle 2 is 86 degrees. Whenever a line is bisected by another line, 4 angles are formed. The opposite angles aka the kissing V's have the same angle measurement. Angle 2 and 86-degrees are the kissing V's here, thus they have the same angle measure.

7 0

2 years ago

Walter buys a bus pass for $30 every time he rides the bus money is deducted from the value of the pass he rode 12 times and $24

klemol [59]

So each time, 24/12 or $2 was deducted per trip

he has 30-24=$6 left

$6/$2=3, he has 3 trips left

I wonder what your question is

6 0

3 years ago

Please help Find: ∠x ∠a ∠b

V125BC [204]

Answer:

your answer

don't forget to mark brainliest✌️✌️

7 0

3 years ago

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced

Butoxors [25]

Answer:

1) $\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

2) $df = c-1 = 2-1$

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

Where c represent the number of categories c=2

And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0

3 years ago

Which number is a factor of 100?<br> 8<br> 12<br> 15<br> 20

vova2212 [387]

Answer:

Step-by-step explanation:

Divisors of 100

1, 2, 4, 5, 10, 20, 25, 50, 100

7 0

3 years ago

Read 2 more answers