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MAXImum [283]
3 years ago
6

Alg 1 please pls help!! this is my last question for today!! which algebraic expression is a polynomial with a degree of 2?

Mathematics
1 answer:
Verdich [7]3 years ago
8 0
I don't quite understand the last answer, do you happen to have an image you can show me?


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PLEASE HELP! Due in a few hours!!<br> You need to workout the area of the shape :)
ivann1987 [24]

Answer:

breakdown the initial figure into 2 rectangle

and add their area

4 0
3 years ago
the solution to the system of equation below is (−2, −1). 2x − 3y = −1 11x − 9y = −13 when the first equation is multiplied by −
Evgen [1.6K]
When the first equation is multiplied by -3, the sum of the two equation and any of the original equations will have the same solution as the original equations. Hence 5x = -10 and 11x - 9x = -13 will have a solution of (-2, -1).
6 0
3 years ago
Jack's train arrived at the station at 8:30 in the evening. The train ride was 2 hours and 10 minutes.
Taya2010 [7]

Answer:

6:20 PM

Step-by-step explanation:

They got there at 8:30 PM, and 2 hours and 10 minutes prior would have been 6:20 PM.

6 0
3 years ago
Using the quadratic formula to solve 2x^2 = 4x – 7, what are the values of x?
LekaFEV [45]

For this case we have the following quadratic equation:

2x ^ 2 = 4x - 7

Rewriting the equation we have:

2x ^ 2 - 4x + 7 = 0

From here, we have:

a=2 b = -4c = 7

Substituting values in the quadratic equation we have:

x = \frac{-b+/-\sqrt{b^2-4ac}}{2a}

x = \frac{-(-4)+/-\sqrt{(-4)^2-4(2)(7)}}{2(2)}

Rewriting the equation we have:

x = \frac{4+/-\sqrt{16-56}}{4}

x = \frac{4+/-\sqrt{-40}}{4}

x = \frac{4+/-\sqrt{-4*10}}{4}

x = \frac{4+/-2i\sqrt{*10}}{4}

x = \frac{2+/-i\sqrt{*10}}{2}

Answer:

The values of x are given by:

x = \frac{2+i\sqrt{*10}}{2}

x = \frac{2-i\sqrt{*10}}{2}

3 0
3 years ago
Read 2 more answers
0 × 0 + 1- 0 ÷ 1 -0 ​
seraphim [82]

Answer:

1

Step-by-step explanation:

0×0=0

1-0=1

when we put into this equation

0+1÷1

1÷1=1

so, 0+1=1

hopefully it works

4 0
3 years ago
Read 2 more answers
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