Alg 1 please pls help!! this is my last question for today!! which algebraic expression is a polynomial with a degree of 2?

Mathematics

1 answer:

Verdich [7]3 years ago

8 0

I don't quite understand the last answer, do you happen to have an image you can show me?

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Given: ∠1 , ∠2 , ∠3 , and ∠4 formed by two intersecting segments. Prove: ∠1 and ∠3 are congruent. The figure shows 2 intersectin

Shkiper50 [21]

Answer:

Angle 1 and angle 3 are congruent by Vertical Angle theorem. It can also be proven using reflection.

Step-by-step explanation:

Two line segments which intersect form one intersection point which has 4 angles from it. Angles 1 and 3 will be directly across from each other off this intersection point. Vertical Angle Theorem states these are congruent.

Angles can be reflected across this intersection point. Since reflection preserves size and shape, these two angles will land on one another and be the same angle.

8 0

3 years ago

Read 2 more answers

1. To the nearest degree, find the measure of angle A.

Assoli18 [71]

Answer:

(1) Option A is correct , The measure of angle A = 26°

(2) Option D is correct, The measure of angle B =70°

Step-by-step explanation:

(1)

In a right angle triangle figure-1 ,

* Hypotenuse(H) is always opposite the right angle and it is always the longest side of the triangle.

* Adjacent side (B) is the non-hypotenuse side that is next to a given angle A.

* Opposite side(P) is across from a given angle A.

To find the Angle A we use the Cosine ratio:

Cosine ratio states that the ratio of the adjacent side of a right triangle to the hypotenuse.

By definition of cosine ratio we have;

$\cos A = \frac{B}{H}$ ....[1]

In the figure - 1 we have B = 18 in and H = 20 in

substitute these in [1] to find angle A

$\cos A =\frac{18}{20} =\frac{9}{10} = 0.9$

$A = cos^{-1} (0.9)$

⇒ $A \approx 26^{\circ}$

therefore, the measure of angle A is, $26^{\circ}$

(2)P

In figure -2

Find the measure of angle B.

First find the side BC, using Pythagoras theorem;

Pythagoras theorem states that in the right angle triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Apply Pythagoras theorem in rt. angle ABC;

$AB^2 = AC^2+BC^2$